document.write( "Question 769706: Suppose the diameter of a circle is 90 inches long and a chord is 54 inches long. Find the distance between the chord and the center of the circle. \n" ); document.write( "
Algebra.Com's Answer #468995 by Cromlix(4381)\"\" \"About 
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Consider a right angled triangle.
\n" ); document.write( "The radius (half the diameter = 45ins)
\n" ); document.write( "is the hypotenuse.
\n" ); document.write( "And half of the chord is the base of
\n" ); document.write( "the right angled triangle = 27ins.
\n" ); document.write( "The distance from the centre is
\n" ); document.write( "represented by the vertical side
\n" ); document.write( "of the triangle
\n" ); document.write( "Vertical side^2 + Base side^2 = Radius^2
\n" ); document.write( "Vertical side^2 = Radius^2 - Base side^2
\n" ); document.write( "Vertical side^2 = 45^2 - 27^2
\n" ); document.write( "Vertical side^2 = 1296
\n" ); document.write( "Vertical side = \"sqrt%281296%29\"
\n" ); document.write( "Distance chord and centre = 36ins
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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