document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=769702>Question 769702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a chord of a circle is 50 inches long and is 60 inches from the center. Find the length of the radius.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468992 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consider a right angled triangle.<BR>\n" );
document.write( "The vertical side = 60ins (Distance<BR>\n" );
document.write( "of chord from centre)<BR>\n" );
document.write( "The base side = 25ins (half of the chord)<BR>\n" );
document.write( "The radius will now constitute the hypotenuse.<BR>\n" );
document.write( "Vertical side^2 + Base side^2 = Hypotenuse^2<BR>\n" );
document.write( "60^2 + 25^2 = Hypotenuse^2<BR>\n" );
document.write( "Hypotenuse^2 = 4225<BR>\n" );
document.write( "Hypotenuse = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284225%29 ALIGN=MIDDLE  ALT=\"sqrt%284225%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Hypotenuse = 65ins<BR>\n" );
document.write( "This is the length of the radius.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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