document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=769642>Question 769642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the length and breadth of a rectangular photo is 3:2. The area of the photo is 864cm square. Find its length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468968 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Taking the ratio 3:2<BR>\n" );
document.write( "3x * 2x = 864<BR>\n" );
document.write( "6x^2 = 864<BR>\n" );
document.write( "x^2 = 144<BR>\n" );
document.write( "x =<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28144%29 ALIGN=MIDDLE  ALT=\"sqrt%28144%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "So, Length = 3* 12 = 36cm<BR>\n" );
document.write( "Breadth = 2 * 12 = 24cm<BR>\n" );
document.write( "36 * 24 = 864cm^2<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );