document.write( "Question 769572: Three cards are numbered 2,3 and 4. List all the possible 3-digit numbers that can be formed when placing the cards on a table next to each other.Find the probability of forming:
\n" ); document.write( "(i)the number 234
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Algebra.Com's Answer #468943 by ramkikk66(644)\"\" \"About 
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document.write( "Three cards are numbered 2,3 and 4. List all the possible 3-digit numbers that can be formed when placing the cards on a table next to each other.Find the probability of forming:\r\n" );
document.write( "(i)the number 234\r\n" );
document.write( "(ii)an odd number\r\n" );
document.write( "(iii)an even number\r\n" );
document.write( "(iv)a number greater than 300\r\n" );
document.write( "Ans:\r\n" );
document.write( "The first digit of the 3 digit number can be formed in 3 ways (any of the 3 cards\r\n" );
document.write( "can be picked).\r\n" );
document.write( "The second in 2 ways (because once the 1st card is picked, you can pick only from\r\n" );
document.write( "the remaining 2)\r\n" );
document.write( "The third in only one way (last card remaining)\r\n" );
document.write( "So the total number of combinations is 3*2*1 = 6. i.e. 6 numbers can be formed.\r\n" );
document.write( "Here they are:\r\n" );
document.write( "234\r\n" );
document.write( "243\r\n" );
document.write( "324\r\n" );
document.write( "342\r\n" );
document.write( "423\r\n" );
document.write( "432\r\n" );
document.write( "i) probability of getting 234 = 1/6 (only one of the 6 numbers is 234)\r\n" );
document.write( "ii) odd number = 2/6 or 1/3 (2 of the 6 numbers are odd)\r\n" );
document.write( "iii) even number = 4/6 or 2/3 (4 of the 6 numbers are even)\r\n" );
document.write( "iv) number > 300 = 4/6 or 2/3 (4 of the 6 numbers are > 300)\r\n" );
document.write( "Hope this helps :)\r\n" );
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