document.write( "Question 768816: a pipe can fill a container with water in 3 hrs. However, if water is drawn from it at the same time at the rate of 4 cubic ft per hour, it requires 5 hrs to fill it. At what rate is the pipe delivering water? \n" ); document.write( "

Algebra.Com's Answer #468921 by Edwin McCravy(20081) $\"\"$ $\"About$

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document.write( "Suppose the container holds x cubic feet of water.\r\n" );
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\n" ); document.write( "a pipe can fill a container with water in 3 hrs.
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document.write( "So the pipe's fill rate is x cu.ft. per 3 hours. or  or \r\n" );
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\n" ); document.write( "However, if water is drawn from it at the same time at the rate of 4 cubic ft per hour,
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document.write( "That means the new slower fill rate is the pipe's original fill rate \r\n" );
document.write( "reduced by  to \r\n" );
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\n" ); document.write( "it requires 5 hrs to fill it.
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document.write( "So this new slower fill rate is also x cu.ft. per 5 hours. or  or .\r\n" );
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document.write( "So we equate the two expressions for the new slower fill rate:\r\n" );
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document.write( " = . \r\n" );
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document.write( "  \r\n" );
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document.write( "Multiply thru by LCD of 15\r\n" );
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document.write( "5x - 60 = 3x\r\n" );
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document.write( "     2x = 60\r\n" );
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document.write( "      x = 30 cu ft, which is how much the container holds.\r\n" );
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\n" ); document.write( "At what rate is the pipe delivering water?
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document.write( "Since the pipe's fill rate is , that becomes:\r\n" );
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document.write( ", or 10,\r\n" );
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document.write( "Edwin

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