document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=769523>Question 769523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having troubling factoring 3z^2+13z+14\r<BR>\n" );
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document.write( "I have tried \r<BR>\n" );
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document.write( "(3z-1)(z-14)<BR>\n" );
document.write( "(3z+1)(3z+14) and I can't get the right answer! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468902 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am having troubling factoring 3z^2+13z+14\r<BR>\n" );
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document.write( "I have tried \r<BR>\n" );
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document.write( "(3z-1)(z-14)<BR>\n" );
document.write( "(3z+1)(3z+14) and I can't get the right answer!<BR>\n" );
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document.write( "3z^2+13z+14 has no negative, so all terms are +<BR>\n" );
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document.write( "(3z+1)(3z+14) won't work, it gives 9z^2<BR>\n" );
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document.write( "Both of your attempts used 1*14 for 14<BR>\n" );
document.write( "Try using 14 = 2*7<BR>\n" );
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