document.write( "Question 769497: the sum of two numbers is 38. three times the smaller number exceeds the larger number by 30. find the numbers
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Algebra.Com's Answer #468887 by 55305(86)\"\" \"About 
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Suppose we assume the two numbers are x and y, with x being the smaller one. The sum of the 2 numbers is \"x%2By=38\", and we are also given that \"3x-y=30\".
\n" ); document.write( "Adding the two equations, we get \"x%2By%2B3x-y=30%2B38\", which simplifies to \"4x=68\". Dividing both sides by 4, we get \"x=17\".
\n" ); document.write( "\"y=38-x=38-17=21\"\r
\n" ); document.write( "\n" ); document.write( "So x=17 and y=21.
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