document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66159>Question 66159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digit number is 9. The number is 6 times the units digit. Find the number. So far I have: a+b=9, then a+6B=n and that's as far as I can get. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46887 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number: 10a + b<BR>\n" );
document.write( "a + b = 9 which can be: a = 9 - b<BR>\n" );
document.write( "and<BR>\n" );
document.write( "10a + b = 6b<BR>\n" );
document.write( "Plug:<BR>\n" );
document.write( "10a + b = 6b<BR>\n" );
document.write( "10(9 - b) = 5b<BR>\n" );
document.write( "90 - 10b = 15b<BR>\n" );
document.write( "90 = 15b<BR>\n" );
document.write( "6 = b<BR>\n" );
document.write( "Plug:<BR>\n" );
document.write( "a = 9 - b = 9 - 6 = 3<BR>\n" );
document.write( "Number: 10a + b = 10(3) + 6 = 30 + 6 = 36 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );