document.write( "Question 66158: From Abu Dhabi to Al-Ain is 149 km. A cyclist starts from Abu Dhabi cycling to Al-Ain at a steady speed of 14 km/hr. An hour later, a car starts from Al-Ain going to Abu Dhabi at a steady speed of 4o km/hr. How far from Abu Dhabi do they meet? \n" ); document.write( "
Algebra.Com's Answer #46885 by stanbon(75887)\"\" \"About 
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From Abu Dhabi to Al-Ain is 149 km. A cyclist starts from Abu Dhabi cycling to Al-Ain at a steady speed of 14 km/hr. An hour later, a car starts from Al-Ain going to Abu Dhabi at a steady speed of 4o km/hr. How far from Abu Dhabi do they meet?
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\n" ); document.write( "Assume they meet x km from their starting point, Abu Dhabi.
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\n" ); document.write( "1st cyclist DATA:
\n" ); document.write( "After one hour he has gone 14 km
\n" ); document.write( "He has x-14 km to go.
\n" ); document.write( "His Rate is 14 km/hr.
\n" ); document.write( "His time is (x-14)/14 hrs.
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\n" ); document.write( "2nd cyclist DATA:
\n" ); document.write( "His total distance is x km
\n" ); document.write( "His rate is 40 km/hr
\n" ); document.write( "His total time is x/40 hrs
\n" ); document.write( "---------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "Time for 1st cyclist x-14 km = Time for 2nd cyclist to go x km.
\n" ); document.write( " (x-14)/14 = x/40
\n" ); document.write( "Cross-multiply to get:
\n" ); document.write( "40x-560=14x
\n" ); document.write( "26x=560
\n" ); document.write( "x=21.54 km
\n" ); document.write( "Conclusion:
\n" ); document.write( "They meet 149-21.54= 127.46 km short of Al-Ain.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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