document.write( "Question 769221: I don't know how to solve this and I can't find anything in my text for this...help please =/
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\n" ); document.write( "The weight in kilograms,W, of a female African elephant at age t years is given by W(t)=2600(1-0.51e^-0.075t). Estimate the age, to the nearest year, of an adult female African elephant weighing 1800 kilograms.
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Algebra.Com's Answer #468845 by ramkikk66(644)\"\" \"About 
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document.write( "The weight in kilograms,W, of a female African elephant at age t years is given by W(t)=2600(1-0.51e^-0.075t). Estimate the age, to the nearest year, of an adult female African elephant weighing 1800 kilograms.\r\n" );
document.write( "Ans:\r\n" );
document.write( "Substituting for Weight as 1800 in the equation, we get\r\n" );
document.write( "\"1800+=+2600%2A%281+-+0.51%2Ae%5E%28-0.075t%29%29\"\r\n" );
document.write( "Simplifying\r\n" );
document.write( "\"%281+-+0.51%2Ae%5E%28-0.075t%29%29+=+1800%2F2600+=+9%2F13\"\r\n" );
document.write( "\"0.51%2Ae%5E%28-0.075t%29+=+0.51%2F%28e%5E%280.075t%29%29+=+1+-+%289%2F13%29+=+0.3077\"\r\n" );
document.write( "\"e%5E%280.075t%29+=+0.51%2F0.3077+=+1.6575\"\r\n" );
document.write( "Taking natural logarithms of both sides\r\n" );
document.write( "\"0.075%2At+=+ln%281.6575%29+=+0.5053\"\r\n" );
document.write( "\"t+=+0.5053%2F0.075+=+6.737\"\r\n" );
document.write( "So age of the elephant rounded off to nearest year is 7 years.\r\n" );
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document.write( "Hope you got it :)\r\n" );
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