document.write( "Question 769390: Eight years ago, Hold was 7 times older than her son. Today, she is exactly 3 times as old as her son.
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document.write( "How old are both Mrs. Hold and her son today? \n" );
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Algebra.Com's Answer #468832 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hold was 7x older than her son. \n" ); document.write( "H = 7S \n" ); document.write( "Eight years later she is exactly \n" ); document.write( "3 x as old as her son. \n" ); document.write( "H + 8 = 3(S + 8) \n" ); document.write( "Replace H with 7S from first equation \n" ); document.write( "7S + 8 = 3(S + 8) \n" ); document.write( "7S + 8 = 3S + 24 \n" ); document.write( "4S = 16 \n" ); document.write( "S = 4 \n" ); document.write( "Ages today. \n" ); document.write( "Son = 12 years old \n" ); document.write( "Mrs. Hold = 36 years old. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |