document.write( "Question 769346: If the width of a rectangle is 4 cm more than one-half of its length and its perimeter is 50 cm. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #468826 by Cromlix(4381) You can put this solution on YOUR website! Length = x \n" ); document.write( "Width = 4 + x/2 \n" ); document.write( "Perimeter = 2*length + 2*width \n" ); document.write( "50 = 2(x) + 2(4 + x/2) \n" ); document.write( "50 = 2x + 8 + x \n" ); document.write( "3x = 42 \n" ); document.write( "x = 14cm \n" ); document.write( "Length = 14cm \n" ); document.write( "Width = 11cm. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |