document.write( "Question 66157: A sum of money of $10000 is invested, partly at 4% and partly at 6%. If the yearly income from the two investments was $530. Find the amount invested at each rate. \n" ); document.write( "

Algebra.Com's Answer #46881 by josmiceli(19441) $\"\"$ $\"About$

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x is amount invested @ 4%
\n" ); document.write( "10,000 - x is amount invested @ 6%
\n" ); document.write( " $\".04x+%2B+.06%2810000+-+x%29+=+530\"$
\n" ); document.write( " $\".04x+%2B+600+-+.06x+=+530\"$
\n" ); document.write( " $\".02x+=+70\"$
\n" ); document.write( " $\"x+=+35000\"$ amount invested @ 4%
\n" ); document.write( " $\"10000+-+x+=+65000\"$ amount invested @ 6% \n" ); document.write( "

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