document.write( "Question 769313: Last week Al bought some golf balls for $20. The next day they were on sale for $0.50 per ball less, and he bought $22.50 worth of balls. If he purchased 5 more balls on the second day than on the first day, how many did he buy each day and at what price per ball? \n" ); document.write( "
Algebra.Com's Answer #468785 by stanbon(75887)\"\" \"About 
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Last week Al bought some golf balls for $20. The next day they were on sale for $0.50 per ball less, and he bought $22.50 worth of balls. If he purchased 5 more balls on the second day than on the first day, how many did he buy each day and at what price per ball?
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\n" ); document.write( "Let original purchase be \"x\" balls at $20
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\n" ); document.write( "Next day value of the ball he bought was [(2000/x)-50)(x+5) = 2250
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\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "(2000-50x)(x+5) = 2250x
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\n" ); document.write( "2000x + 10000 - 50x^2 - 250x = 2250x
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\n" ); document.write( "50x^2 +500x - 10000 = 0
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\n" ); document.write( "x^2 + 10x - 200 = 0
\n" ); document.write( "(x+20)(x-10) = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 10 (# purchased on 1st day)
\n" ); document.write( "x+5 = 15 (# purchased on 2nd day)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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