document.write( "Question 769309: if i invested $3805 in an account that pays 6.5% compounded weekly. What will be the balance in the account after two score years?_________________ \n" ); document.write( "
Algebra.Com's Answer #468784 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! if i invested $3805 in an account that pays 6.5% compounded weekly. What will be the balance in the account after two score years? \n" ); document.write( "*** \n" ); document.write( "compound interest formula: A=P(1+i)^n, P=initial investment, i=interest rate per compounding period, n=number of compounding periods, A=amount after n-periods. \n" ); document.write( "For given problem: \n" ); document.write( "P=$3805 \n" ); document.write( "i=.065/52=0.00125 \n" ); document.write( "n=40*52=2080 (one score=20 yrs) \n" ); document.write( "A=? \n" ); document.write( ".. \n" ); document.write( "A=3805(1+.00125)^2080 \n" ); document.write( "A=3805(1.00125)^2080≈51146 \n" ); document.write( "The balance in the account after two score years=$51,146 \n" ); document.write( " |