document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=769297>Question 769297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation:\r<BR>\n" );
document.write( "\n" );
document.write( "(2)/(3-t)+(1)/(3+t)+(1)/(9-t^2)=0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468774 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
document.write( "(1) 2/(3-t) + 1/(3+t) + 1/(9-t^2) = 0<BR>\n" );
document.write( "Note that the denominator of the third term factors into<BR>\n" );
document.write( "(2) 9-t^2 = (3+t)*(3-t)<BR>\n" );
document.write( "If we multiply both sides of (1) by (2) we get<BR>\n" );
document.write( "(3) 2*(3+t) + (3-t) +1 = 0 or<BR>\n" );
document.write( "(4) 6+2t +3-t +1 = 0 or<BR>\n" );
document.write( "(5) t + 10 = 0 or<BR>\n" );
document.write( "(6) t = -10<BR>\n" );
document.write( "Is (2/13 + 1/(-7) - 1/91 = 0)?<BR>\n" );
document.write( "Is (14/91 - 13/91 - 1/91 = 0)?<BR>\n" );
document.write( "Is (1/91 - 1/91 = 0)?<BR>\n" );
document.write( "Is (0 = 0)? Yes<BR>\n" );
document.write( "Answer: t = -10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );