document.write( "Question 769288: How do I Graph y<4x+2? \n" ); document.write( "
Algebra.Com's Answer #468762 by Edwin McCravy(20059)\"\" \"About 
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How do I Graph y < 4x + 2
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document.write( "We draw the boundary line which has the equation that is\r\n" );
document.write( "like the inequality except that it has an equal sign instead\r\n" );
document.write( "of a \"<\".\r\n" );
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document.write( "Boundary line's equation is y = 4x + 2.\r\n" );
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document.write( "Letting x = 0, we get y = 4(0) + 2 = 2, so (0,2) is a point on the line.\r\n" );
document.write( "Letting x - -1, we get y = 4(-1) + 2 = -2, so (-1,-2) is a point on the line.\r\n" );
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document.write( "We plot those and draw a dotted line through them, dotted because\r\n" );
document.write( "the solution set does not include its boundary line, since the\r\n" );
document.write( "inequality is <, and not <.\r\n" );
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document.write( "Then we pick a test point not on the line.  We can pick (0,0) since\r\n" );
document.write( "it is not on the line.  We test to see if (0,0) is a solution or not.\r\n" );
document.write( "We substitute it in the original inequality:\r\n" );
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document.write( "y < 4x + 2\r\n" );
document.write( "0 < 4(0) + 2\r\n" );
document.write( "0 < 2\r\n" );
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document.write( "That is true, so all the solutions are on the same side of the\r\n" );
document.write( "boundary line that the origin is on, so we shade that side of the line:\r\n" );
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document.write( "  Edwin
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