document.write( "Question 66092: A square picture has a 1-centimeter border around it. Half of the total area of the picture and the border is made up by the border. Use a graph to determine the dimensions of the picture to the nearest tenth centimeter.\r
\n" ); document.write( "\n" ); document.write( "Choices:\r
\n" ); document.write( "\n" ); document.write( "A) 2.4cm by 2.4cm
\n" ); document.write( "B) 4.8cm by 4.8cm
\n" ); document.write( "C) 2cm by 2cm
\n" ); document.write( "D) 4.1 cm by 4.1cm
\n" ); document.write( "

Algebra.Com's Answer #46874 by venugopalramana(3286)\"\" \"About 
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A square picture has a 1-centimeter border around it. Half of the total area of the picture and the border is made up by the border. Use a graph to determine the dimensions of the picture to the nearest tenth centimeter.
\n" ); document.write( " Choices:
\n" ); document.write( " A) 2.4cm by 2.4cm
\n" ); document.write( " B) 4.8cm by 4.8cm
\n" ); document.write( " C) 2cm by 2cm
\n" ); document.write( " D) 4.1 cm by 4.1cm
\n" ); document.write( "BORDER WIDTH = 1 CM
\n" ); document.write( "LET PICTURE BE OF SIDE X CM.
\n" ); document.write( "AREA OF PICTURE = X^2
\n" ); document.write( "HENCE INCLUDING BORDER OF 1 CM ON ALL SIDES, THE SQUARE WILL BE
\n" ); document.write( "OF SIDE (X+1+1)=X+2
\n" ); document.write( "AREA OF PICTURE WITH BORDER =(X+2)^2
\n" ); document.write( "AREA OF BORDER=(X+2)^2-2X^2
\n" ); document.write( "WE GOT
\n" ); document.write( "(X+2)^2-X^2=[(X+2)^2]/2= Y SAY
\n" ); document.write( "WE CAN SOLVE THIS BY DRAWING GRAPHS OF
\n" ); document.write( "Y=2X^2...AND...........Y=(X+2)^2.........
\n" ); document.write( "
\n" ); document.write( "WE FIND THAT THE 2 CURVES INTERSECT AT X=4.8 CM
\n" ); document.write( "HENCE THE PICTURE WITH BORDER HAS
\n" ); document.write( "6.8 CM SIDE AND PICTURE HAS 4.8 CM SIDE.
\n" ); document.write( "
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