document.write( "Question 769226: the area of sqare decreases 7 sq units by decreasing length 5 cms and by increasing breadth 3cms.if length increases 3 cms and breadth increases 2 cms then area
\n" ); document.write( "will increase 62 sq units.what is the lengh of the squareż
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Algebra.Com's Answer #468730 by josgarithmetic(39617)\"\" \"About 
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Side length original square, s.
\n" ); document.write( "Original area, \"s%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "If sides become s-5 and s+3, then \"s%5E2-%28s-5%29%28s%2B3%29=7\"
\n" ); document.write( "If sides become s+3 and s+2, then \"%28s%2B3%29%28s%2B2%29-s%5E2=62\"
\n" ); document.write( "Find s.\r
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\n" ); document.write( "\n" ); document.write( "The \"7\" equation:
\n" ); document.write( "\"s%5E2-+%28+s%5E2-5s%2B3s-15%29=7\"
\n" ); document.write( "\"s%5E2-%28s%5E2-2s-15%29=7\"
\n" ); document.write( "\"s%5E2-s%5E2%2B2s%2B15=7\"
\n" ); document.write( "\"2s=7-15=-8\"
\n" ); document.write( "\"s=-4\" which is nonsense.\r
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\n" ); document.write( "\n" ); document.write( "The \"62\" equation:
\n" ); document.write( "\"s%5E2%2B5s%2B6-s%5E2=62\"
\n" ); document.write( "\"5s%2B6=62\"
\n" ); document.write( "\"5s=62-6\"
\n" ); document.write( "\"5s=56\"
\n" ); document.write( "\"highlight%28s=56%2F5=11%261%2F5%29\"\r
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\n" ); document.write( "\n" ); document.write( "Something is wrong in your description. The first part fails but the second part succeeds.
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