document.write( "Question 769041: Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers)\r
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document.write( "If you have a body temperature of 99.00 °F, what is your percentile score?
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document.write( " a) 90
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document.write( " b)92
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document.write( "c) 94
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document.write( " d)96 \n" );
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Algebra.Com's Answer #468651 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers) \n" ); document.write( "If you have a body temperature of 99.00 °F, what is your percentile score? \n" ); document.write( "----- \n" ); document.write( "z(99) = (99-98.2)/0.62 = 0.8/0.62 = 1.2903 \n" ); document.write( "---- \n" ); document.write( "P(z < 1.2903) = normalcdf(-100,1.2903) = 0.9015 \n" ); document.write( "------ \n" ); document.write( "Ans: 90%ile \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( "a) 90 \n" ); document.write( "b)92 \n" ); document.write( "c) 94 \n" ); document.write( "d)96 \n" ); document.write( " \n" ); document.write( " |