document.write( "Question 769041: Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers)\r
\n" ); document.write( "\n" ); document.write( "If you have a body temperature of 99.00 °F, what is your percentile score?
\n" ); document.write( " a) 90
\n" ); document.write( " b)92
\n" ); document.write( "c) 94
\n" ); document.write( " d)96
\n" ); document.write( "

Algebra.Com's Answer #468651 by stanbon(75887)\"\" \"About 
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Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers)
\n" ); document.write( "If you have a body temperature of 99.00 °F, what is your percentile score?
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\n" ); document.write( "z(99) = (99-98.2)/0.62 = 0.8/0.62 = 1.2903
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\n" ); document.write( "P(z < 1.2903) = normalcdf(-100,1.2903) = 0.9015
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\n" ); document.write( "Ans: 90%ile
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "a) 90
\n" ); document.write( "b)92
\n" ); document.write( "c) 94
\n" ); document.write( "d)96
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