document.write( "Question 769001: What is the focal point of the ellipse (x+3)^2/16 + (y-1)^2/4 ? \n" ); document.write( "
Algebra.Com's Answer #468650 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
What is the focal point of the ellipse (x+3)^2/16 + (y-1)^2/4 ?
\n" ); document.write( "***
\n" ); document.write( "\"%28x%2B3%29%5E2%2F16+%2B+%28y-1%29%5E2%2F4=1\"
\n" ); document.write( "This is an equation of an ellipse with horizontal major axis.
\n" ); document.write( "Its standard form: \"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\", a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given ellipse:
\n" ); document.write( "center: (-3,1)
\n" ); document.write( "a^2=16
\n" ); document.write( "b^2=4
\n" ); document.write( "c^2=a^2-b^2=16-4=12
\n" ); document.write( "c=√12≈3.46 (distance from center to foci on horizontal major axis)
\n" ); document.write( "foci: (-3±c, 1)=(-3±3.46,1)=(0.46,1) and (-6.46,1) (note: ellipses have 2 focal points)
\n" ); document.write( " \n" ); document.write( "
\n" );