document.write( "Question 769038: Y=-6x+6\r
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Algebra.Com's Answer #468637 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the equation of the line that is parallel to this line and passes through the point (7,5):\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"-6\" (its from the slope of \"y=-6%2Ax%2B6\" which is also \"-6\").\n" ); document.write( "Also since the unknown line goes through (7,5), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-5=-6%2A%28x-7%29\" Plug in \"m=-6\", \"x%5B1%5D=7\", and \"y%5B1%5D=5\"
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\n" ); document.write( " \"y-5=-6%2Ax%2B%286%29%287%29\" Distribute \"-6\"
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\n" ); document.write( " \"y-5=-6%2Ax%2B42\" Multiply
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\n" ); document.write( " \"y=-6%2Ax%2B42%2B5\"Add \"5\" to both sides to isolate y
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\n" ); document.write( " \"y=-6%2Ax%2B47\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=-6%2Ax%2B6\" and goes through (\"7\",\"5\") is \"y=-6%2Ax%2B47\"
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\n" ); document.write( " So here are the graphs of the equations \"y=-6%2Ax%2B6\" and \"y=-6%2Ax%2B47\"
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\n" ); document.write( " graph of the given equation \"y=-6%2Ax%2B6\" (red) and graph of the line \"y=-6%2Ax%2B47\"(green) that is parallel to the given graph and goes through (\"7\",\"5\")
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\n" ); document.write( "\n" ); document.write( "the equation of the line that is perpendicular to this line and passes through the point(7,5):\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"-6\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%28-6%2F1%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%281%2F-6%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=1%2F6\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"1%2F6\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"1%2F6\" (its the negative reciprocal of \"-6\" from the line \"y=-6%2Ax%2B6\").\n" ); document.write( "Also since the unknown line goes through (7,5), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-5=%281%2F6%29%2A%28x-7%29\" Plug in \"m=1%2F6\", \"x%5B1%5D=7\", and \"y%5B1%5D=5\"
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\n" ); document.write( " \"y-5=%281%2F6%29%2Ax-%281%2F6%29%287%29\" Distribute \"1%2F6\"
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\n" ); document.write( " \"y-5=%281%2F6%29%2Ax-7%2F6\" Multiply
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\n" ); document.write( " \"y=%281%2F6%29%2Ax-7%2F6%2B5\"Add \"5\" to both sides to isolate y
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\n" ); document.write( " \"y=%281%2F6%29%2Ax-7%2F6%2B30%2F6\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%281%2F6%29%2Ax%2B23%2F6\" Combine the fractions
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\n" ); document.write( " \"y=%281%2F6%29%2Ax%2B23%2F6\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=-6%2Ax%2B6\" and goes through (\"7\",\"5\") is \"y=%281%2F6%29%2Ax%2B23%2F6\"
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\n" ); document.write( " So here are the graphs of the equations \"y=-6%2Ax%2B6\" and \"y=%281%2F6%29%2Ax%2B23%2F6\"
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\n" ); document.write( " graph of the given equation \"y=-6%2Ax%2B6\" (red) and graph of the line \"y=%281%2F6%29%2Ax%2B23%2F6\"(green) that is perpendicular to the given graph and goes through (\"7\",\"5\")
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