document.write( "Question 769002: Please someone help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "*Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice the shorter side. Find its length and width.\r
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Algebra.Com's Answer #468617 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Since the rectangles are similar, the relationships between the length and width are the same, so we can write it\r
\n" ); document.write( "\n" ); document.write( "let \"x\" be the shorter side\r
\n" ); document.write( "\n" ); document.write( "\"%282x%2B8%29%2Fx+=+12%2F5\"........cross multiply\r
\n" ); document.write( "\n" ); document.write( "\"5%282x%2B8%29+=+12x\"\r
\n" ); document.write( "\n" ); document.write( "\"10x+%2B+40+=+12x\"\r
\n" ); document.write( "\n" ); document.write( "\"40+=+12x+-+10x\"\r
\n" ); document.write( "\n" ); document.write( "\"40+=+2x\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+40%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+20cm\"...... the shorter side
\n" ); document.write( "then the longer side is:\r
\n" ); document.write( "\n" ); document.write( "\"2%2820%29%2B8+=+48cm\" \r
\n" ); document.write( "\n" ); document.write( "so, the 2nd rectangle is \"48\" by \"20\"\r
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