document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=768857>Question 768857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If sin qita = 1/3 , the find the value of 2 cot^2 qita + 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468609 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If sin qita = 1/3 , the find the value of 2 cot^2 qita + 2<BR>\n" );
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document.write( "use x for qita<BR>\n" );
document.write( "sin x=1/3<BR>\n" );
document.write( "cos x=&#8730;(1-sin^2x)=&#8730;(1-1/9)=&#8730;(8/9)=&#8730;8/3<BR>\n" );
document.write( "cot x=cos x/sin x=1/&#8730;8<BR>\n" );
document.write( "cot^2 x=1/8<BR>\n" );
document.write( "2 cot^2 x+2=x=1/4+2=9/4 </SPAN>\n" );
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