document.write( "Question 768973: I need help please. \r
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document.write( "Solve squrrt2x + x = 4 for x.\r
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document.write( "I got lost, so my answer isn't an option. Not sure where I went wrong. \r
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document.write( "sqrrt2x + x = 4
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document.write( "sqrrt2x -x = 4 - x
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document.write( "sqrrt2x = 4-x
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document.write( "(squrrt2x)^2 = (4-x)^2
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document.write( "2x = 16-4x-4x+x
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document.write( "2x = 16-8x+x
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document.write( "2x = 16-7x
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document.write( "16-9x
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document.write( "-16/9 = x?\r
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document.write( "Answer Options:\r
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document.write( "A. x = 2
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document.write( "B. The two solutions are complex numbers.
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document.write( "C. x = 4 or x = -4
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document.write( "D. x = 2 x = 8 \n" );
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Algebra.Com's Answer #468590 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Solve sqrt(2x) + x = 4 for x. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "square both sides \n" ); document.write( "2x=16-8x+x^2 \n" ); document.write( "x^2-10x+16=0 \n" ); document.write( "(x-8)(x-2)=0 \n" ); document.write( "x=8 \n" ); document.write( "or \n" ); document.write( "x=2 \n" ); document.write( " \n" ); document.write( " |