document.write( "Question 66138: The sum of the digits of a two-digit number is 7. The tens digit is 7 more than twice the units digit. Find the number. \n" ); document.write( "
Algebra.Com's Answer #46854 by josmiceli(19441)\"\" \"About 
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The number is \"10a+%2B+b\" The digits are a and b
\n" ); document.write( "\"a+%2B+b+=+7\"
\n" ); document.write( "\"a+=+2b+%2B+7\"
\n" ); document.write( "\"b+=+7+-+a\"
\n" ); document.write( "\"a+=+2%287+-+a%29+%2B+7\"
\n" ); document.write( "\"a+=+14+-+2a+%2B+7\"
\n" ); document.write( "\"a+=+21+-+2a\"
\n" ); document.write( "\"3a+=+21\"
\n" ); document.write( "\"a+=+7\"
\n" ); document.write( "\"7+%2B+b+=+7\"
\n" ); document.write( "\"b+=+0\"
\n" ); document.write( "The number is 70
\n" ); document.write( "If b were 1 or greater, a would turn out to be 9 or higher, and
\n" ); document.write( "a can't be greater than 7
\n" ); document.write( "\"a+=+2%2A1+%2B+7\"
\n" ); document.write( "\"a+=+9\"
\n" ); document.write( "
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