document.write( "Question 66139: One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture? Here's what I have so far: 10x+35(25-x)=400 but I don't know if it's right or what to do next. \n" ); document.write( "
Algebra.Com's Answer #46853 by josmiceli(19441)\"\" \"About 
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\".1x+%2B+.35%28400+-+x%29+=+.25%2A400\"
\n" ); document.write( "\".1x+%2B+140+-+.35x+=+100\"
\n" ); document.write( "\"-.25x+=+-40\"
\n" ); document.write( "\"x+=+160\"
\n" ); document.write( "\"400+-+x+=+240\"
\n" ); document.write( "You must mix 160 gallons of the 10% gasohol with 240 gallons
\n" ); document.write( "of the 35% gasohol to get 400 gallons of the 25% gasohol
\n" ); document.write( "check
\n" ); document.write( "\".1x+%2B+.35%28400+-+x%29+=+.25%2A400\"
\n" ); document.write( "\".1%2A160+%2B+.35%2A240+=+100\"
\n" ); document.write( "\"16+%2B+84+=+100\"
\n" ); document.write( "\"100+=+100\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );