document.write( "Question 768767: how in the world do you do this? thanks!\r
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\n" ); document.write( "\n" ); document.write( "SQRT(4a + 1) = 1
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\n" ); document.write( "CUBERT(3x - 8) = 1
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\n" ); document.write( " SQRT(x + 4) = SQRT(x) - 2
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Algebra.Com's Answer #468493 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Limiting just to the CUBERT item:\r
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\n" ); document.write( "\n" ); document.write( "\"root%283%2C%283x-8%29%29=1\"
\n" ); document.write( "\"%28root%283%2C%283x-8%29%29%29%5E3=1%5E3\"
\n" ); document.write( "\"3x-8=1\"
\n" ); document.write( "\"3x=1%2B8\"
\n" ); document.write( "\"3x=9\"
\n" ); document.write( "\"x=9%2F3=3\"
\n" ); document.write( "x=3
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