document.write( "Question 768727: Find the solution set:
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document.write( "x^3+x^2-7x-3\r
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document.write( "Hint: the possible rational roots are factors of 3 \n" );
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Algebra.Com's Answer #468487 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! The request implies the cubic expression is equated to 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking the root, -3 with synthetic division, the quotient is x^2-2x-1. The REAL and rational root is x=-3. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The synthetic division supporting this is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3___|____1____1____-7____-3 \n" ); document.write( "_____|____ ___-3____6_____3 \n" ); document.write( "_____|______________________ \n" ); document.write( "__________1___-2____-1____0----------see, the remainder is 0.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you work further with the resulting quadratic, you'll find the irrational roots |