document.write( "Question 768574: A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1706 miles required 53 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city? \n" ); document.write( "
Algebra.Com's Answer #468402 by ramkikk66(644)\"\" \"About 
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\n" ); document.write( "A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1706 miles required 53 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?
\n" ); document.write( "Ans:
\n" ); document.write( "Let x miles be driven in the city.
\n" ); document.write( "Then miles driven in highway = 1706 - x
\n" ); document.write( "Gasolene required for city driving = x/27
\n" ); document.write( "Gasolene required for highway = (1706 - x)/38
\n" ); document.write( "Total gasoline = \"%28x%2F27%29+%2B+%281706+-+x%29%2F38+=+53\"
\n" ); document.write( "Multiplying by LCM of 27 and 38 which is 1026, to eliminate the denominator
\n" ); document.write( "\"38%2Ax+%2B+%281706+-+x%29%2A27+=+53%2A1026+=+54378\"
\n" ); document.write( "Simplifying and grouping like terms
\n" ); document.write( "\"38%2Ax+%2B+46062+-+27%2Ax+=+54378\"
\n" ); document.write( "\"11%2Ax+=+8316\"
\n" ); document.write( "\"x+=+756\"
\n" ); document.write( "So miles driven in city = 756
\n" ); document.write( "Miles driven in highway = 1706 - 756 = 950\r
\n" ); document.write( "\n" ); document.write( "Hope you got it :) \n" ); document.write( "
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