document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66125>Question 66125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The greenhouse floor has a diagonal equal to 28 feet. The sides are square. What is the length of one side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46838 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The greenhouse floor has a diagonal equal to 28 feet. The sides are square. What is the length of one side?\r<BR>\n" );
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document.write( "We'll use the Pythagorean Theorem:\r<BR>\n" );
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document.write( "28^2=s^2+s^2<BR>\n" );
document.write( "28^2=2s^2  take sqrt of both sides:\r<BR>\n" );
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document.write( "28=s(sqrt2)\r<BR>\n" );
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document.write( "s=28/sqrt2=19.799 feet\r<BR>\n" );
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document.write( "ck\r<BR>\n" );
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document.write( "(19.799)^2+(19.799)^2=28^2\r<BR>\n" );
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document.write( "392.005+392.005=784<BR>\n" );
document.write( "784.010~~784\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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