document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=768528>Question 768528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man can row a boat 4 miles per hour in still water. If he can row downstream three times as fast as he can row upstream, find the rate of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468374 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468374\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man can row a boat 4 miles per hour in still water. If he can row downstream three times as fast as he can row upstream, find the rate of the current.\r<BR>\n" );
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document.write( "let speed of current = y\r<BR>\n" );
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document.write( "Upstream speed = (4-y)\r<BR>\n" );
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document.write( "Down stream speed = (4+y)\r<BR>\n" );
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document.write( "(4+y) = 3(4-y)\r<BR>\n" );
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document.write( "4+y = 12-3y\r<BR>\n" );
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document.write( "4y=12-4\r<BR>\n" );
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document.write( "4y=8<BR>\n" );
document.write( "y=2\r<BR>\n" );
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document.write( "speed of current = 2 mph </SPAN>\n" );
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