document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=768555>Question 768555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the line parallel to 2x + 6y = -3 and passes through the y-axis at -3/4  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468367 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  2x + 6y = -3 and passes through the y-axis at -3/4 \r<BR>\n" );
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document.write( "6y= -2x-3\r<BR>\n" );
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document.write( "y= -2/6 x -1/2\r<BR>\n" );
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document.write( "slope = m = -1/3\r<BR>\n" );
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document.write( "the parallel line will have same slope \r<BR>\n" );
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document.write( "passing through (0,-3/4)\r<BR>\n" );
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document.write( "So the equation is y = (-1/3)x-(3/4) </SPAN>\n" );
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