document.write( "Question 768499: A flask contains 500 ml of an 80% alcohol solution in water. How much of this solution must be drawn off and replaced by water to obtain a solution having a concentration of 25% alcohol?\r
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document.write( "what are the steps to solve this problem? i get confused when there are already situations where you have to replace and to draw off things in the problem. Thankyou :) \n" );
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Algebra.Com's Answer #468364 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! This calculation will be simpler than if you were replacing the solution with a different concentration of alcohol solution. \n" ); document.write( "- \n" ); document.write( "You begin with a liquid of 500 ml. volume, and you finish with a liquid of 500 ml. volume. When you perform the replacement with the water, you are adding NO alcohol. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let v = volume in milliliters to remove, before replacing with the v of water. \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( "This is using decimal fractions, being my attempt to make this seem less confusing (maybe it works, maybe not). \n" ); document.write( "The equation is in this case, perfectly equivalent to \n" ); document.write( " \n" ); document.write( "or if desired, equivalent to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SOLVE FOR v.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------ \n" ); document.write( "Do the arithmetic and find v = 343.75 ml. but in practice it should really be 343 or 344. \n" ); document.write( " |