document.write( "Question 761271: How do I write the equation of the hyperbola in standard form?\r
\n" ); document.write( "\n" ); document.write( "4x^2-9y^2-8x+54y = 113
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Algebra.Com's Answer #468302 by lwsshak3(11628)\"\" \"About 
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How do I write the equation of the hyperbola in standard form?
\n" ); document.write( "4x^2-9y^2-8x+54y = 113
\n" ); document.write( "4x^2-8x-9y^2+54y = 113
\n" ); document.write( "complete the square:
\n" ); document.write( "4(x^2-2x+1)-9(y^2+6y+9) = 113+4-81
\n" ); document.write( "4(x-1)^2-9(y+3)^2=36
\n" ); document.write( "\"%28x-1%29%5E2%2F9-%28y%2B3%29%5E2%2F4=1\"
\n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis.
\n" ); document.write( "Its standard form: \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of the center
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