document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=768392>Question 768392</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Starting at middle E with a frequency of 328 cps, find the fequency of the note five half-steps above middle E. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468272 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Starting at middle E with a frequency of 328 cps, find the fequency of the note five half-steps above middle E.<BR>\n" );
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document.write( "That's the note A.<BR>\n" );
document.write( "A C# E is a major triad, so A:E = 4:6 --> A below E @ 328 is 328*4/6<BR>\n" );
document.write( "The E an octave up is 2x that, = 328*4/3 Hz<BR>\n" );
document.write( "=~ 437.33 Hz<BR>\n" );
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document.write( "Another approach:<BR>\n" );
document.write( "Each half-note = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=root%2812%2C2%29 ALIGN=MIDDLE  ALT=\"root%2812%2C2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=328%2Aroot%2812%2C2%5E5%29 ALIGN=MIDDLE  ALT=\"328%2Aroot%2812%2C2%5E5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A =~ 437.83 Hz<BR>\n" );
document.write( " </SPAN>\n" );
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