document.write( "Question 768399: Age of chetan in 2002 was 1/90 of his birthyear.wat is his age in 2006?
\n" );
document.write( "30
\n" );
document.write( "28
\n" );
document.write( "26
\n" );
document.write( "22
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #468263 by abdullahkhawer(5)![]() ![]() You can put this solution on YOUR website! In these type of questions the birth year is not known. Therefore, we will have to check all answers. \n" ); document.write( "----------- \n" ); document.write( "Checking of Answers: \n" ); document.write( "Let the birth year be x. \n" ); document.write( "Let y = (1/90 * x) = chetan's age in 2002 \n" ); document.write( "Therefore, x = 90 * y = birth year \n" ); document.write( "If y = 30 then x = 2700 > 2002. Therefore, this option is not possible. \n" ); document.write( "If y = 28 then x = 2520 > 2002. Therefore, this option is not possible. \n" ); document.write( "If y = 26 then x = 2340 > 2002. Therefore, this option is not possible. \n" ); document.write( "If y = 22 then x = 1980 < 2002. Therefore, this option is possible. \n" ); document.write( "Therefore, chetan is 22 years old in 2002. \n" ); document.write( "----------- \n" ); document.write( "Question: \n" ); document.write( "what is his age in 2006? \n" ); document.write( "As chetan is 22 years old in 2002, therefore his age in 2006 will be 22 + 4 = 26 because the difference b/w 2002 and 2006 is 4. \n" ); document.write( "----------- \n" ); document.write( "Ans: \n" ); document.write( "Chetan is 26 years old in 2006 \n" ); document.write( "----------- \n" ); document.write( "Summary: \n" ); document.write( "You just have to check the possibility of answers using the above mentioned method. And then just add the value of difference in the value of possible answer. \n" ); document.write( "----------- \n" ); document.write( "Remarks: \n" ); document.write( "I hope that helped you. :) \n" ); document.write( " |