document.write( "Question 768385: If x men working together at the same rate can complete a job in h hours, what part of the same job can one man working alone complete in k hours?
\n" ); document.write( "a. k/xh
\n" ); document.write( "b. h/xk
\n" ); document.write( "c. k/x+h
\n" ); document.write( "d. kh/h
\n" ); document.write( "e. kx/h
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Algebra.Com's Answer #468252 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
Each man contributes his own part of the job rate so rates are additive. One man takes x times longer than x men. \r
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\n" ); document.write( "\n" ); document.write( "x men__________________h hours for 1 job
\n" ); document.write( "1 man__________________h*x hours for 1 job\r
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\n" ); document.write( "\n" ); document.write( "-----------
\n" ); document.write( "Having the one-man rate of \"1%2F%28hx%29\" job per hour you also can say the rate is \"hx\" hours per job. \r
\n" ); document.write( "\n" ); document.write( "If you want the man to do work for k hours, then:
\n" ); document.write( "\"k%2A%281%2F%28hx%29%29\" \"hour%2A%28job%2Fhour%29\"
\n" ); document.write( "\"k%2F%28hx%29\" job.
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