document.write( "Question 768338: please help me to solve this problem:
\n" ); document.write( "(divide the number in three parts such that the second part is twice the first and the third part is 7 less than the second.)
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Algebra.Com's Answer #468224 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
parts x, y, z.
\n" ); document.write( "The number, Q=x+y+z
\n" ); document.write( "\"y=2x\"
\n" ); document.write( "\"z=-7%2By\"\r
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\n" ); document.write( "\n" ); document.write( "Question is: Find Q.
\n" ); document.write( "\"Q=x%2B2x%2By-7\"
\n" ); document.write( "\"Q=3x%2B2x-7\"
\n" ); document.write( "\"Q=5x-7\" and this is a far as can be found. You need more information to go any more.
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