document.write( "Question 768030: Solve the equation sqr3 sinx = 1/2 sec x for 0 deg < x < 360 deg. \n" ); document.write( "
Algebra.Com's Answer #468222 by lwsshak3(11628)\"\" \"About 
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Solve the equation sqr3 sinx = 1/2 sec x for 0 deg < x < 360 deg.
\n" ); document.write( "√3sinx=(1/2)secx=(1/2)(1/cosx)=1/2cosx
\n" ); document.write( "1/2sinxcosx=√3
\n" ); document.write( "1/sin2x=√3
\n" ); document.write( "sin2x=1/√3=√3/3
\n" ); document.write( "2x≈35.26º, 144.73º
\n" ); document.write( "x≈17.63º, 72.37º
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