document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66101>Question 66101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the slope of any line perpendicular to the line through points (0,5) and <BR>\n" );
document.write( "          (-3, -4).\r<BR>\n" );
document.write( "\n" );
document.write( "what i've done so far is the following:\r<BR>\n" );
document.write( "\n" );
document.write( "m= -4-5/ -3 - 0 = 9/3=3\r<BR>\n" );
document.write( "\n" );
document.write( "I don't know how or what am i suppost to do the rest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46820 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The key here is remembering that perpendicular lines have slopes that are the negative reciprocal of each other.<BR>\n" );
document.write( "So, if your first line has a slope of 3, then any line that is perpendicular to this will have a slope that is the negative reciprocal of 3 or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );