document.write( "Question 768200: Forty-nine items are randomly selected from a population of 500 items. The sample mean is 40 and the sample standard deviation 9.\r
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document.write( "Develop a 99 percent confidence interval for the population mean? (Round your answers to 3 decimal places.)\r
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document.write( "thanks in advance for your help! \n" );
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Algebra.Com's Answer #468198 by stanbon(75887) ![]() You can put this solution on YOUR website! Forty-nine items are randomly selected from a population of 500 items. The sample mean is 40 and the sample standard deviation 9. \n" ); document.write( "Develop a 99 percent confidence interval for the population mean? (Round your answers to 3 decimal places.) \n" ); document.write( "----- \n" ); document.write( "sample mean = x-bar = 40 \n" ); document.write( "---- \n" ); document.write( "ME = z*s/sqrt(n) = 2.5758*9/sqrt(49) = 3.3118 \n" ); document.write( "------------------- \n" ); document.write( "99% CI: 40-3.3118 < u < 40+3.3118 \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |