document.write( "Question 768228: Find the minor axis vertices on the ellipse x^2 + 4y^2 + 12x - 32 y +96 = 0? I don't understand how to do this, thanks in advance for your help!
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Algebra.Com's Answer #468161 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"x%5E2+%2B+4y%5E2+%2B+12x+-+32+y+%2B96+=+0\".....rearrange terms\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B+12x+%2B+4y%5E2++-+32+y+%2B96=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2+%2B+12x%2B_+%29%2B+%284y%5E2++-+32y+%2B_%29%2B96=0\".......complete the square, write \"96\" as
\n" ); document.write( "\"100-4\" then write \"100\" as \"36%2B64\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+12x%2B36+%2B+4y%5E2++-+32y+%2B64-4=0\"....group\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2+%2B+12x%2B36+%29%2B+4%28y%5E2++-+8y+%2B16%29-4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B6+%29%5E2%2B+4%28y++-+4%29%5E2-4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B6+%29%5E2%2B+4%28y++-+4%29%5E2=4\".......both sides divide by \"4\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B6+%29%5E2%2F4%2B+4%28y++-+4%29%5E2%2F4=4%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B6+%29%5E2%2F4%2B+%28y++-+4%29%5E2%2F1=1\"\r
\n" ); document.write( "\n" ); document.write( "\"h=-6\" and \"k=4\",
\n" ); document.write( "\"a=2\" and \"b=1\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=4%2B1\"
\n" ); document.write( "\"c=sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "The distance from the center to either focus is the fixed value \"c\". The distance from the center to a vertex is the fixed value \"a\".\r
\n" ); document.write( "\n" ); document.write( " so center is at (\"-6\",\"4\")\r
\n" ); document.write( "\n" ); document.write( "the length of the whole major axis is \"a=2\"\r
\n" ); document.write( "\n" ); document.write( "the length of the whole minor axis is \"b=1\"\r
\n" ); document.write( "\n" ); document.write( "vertices: (\"-8\",\"4\") and (\"-4\",\"4\")\r
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