document.write( "Question 768228: Find the minor axis vertices on the ellipse x^2 + 4y^2 + 12x - 32 y +96 = 0? I don't understand how to do this, thanks in advance for your help!
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #468152 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Find the minor axis vertices on the ellipse x^2 + 4y^2 + 12x - 32 y +96 = 0?
\n" ); document.write( "***
\n" ); document.write( "x^2+ 12x + 4y^2 - 32 y +96 = 0
\n" ); document.write( "complete the square:
\n" ); document.write( "(x^2+12x+36)+4(y^2-8y+16)=-96+36+64
\n" ); document.write( "(x+6)^2+4(y-4)^2=4
\n" ); document.write( "(x+6)^2/4+(y-4)^2=1
\n" ); document.write( "This is an equation of an ellipse with horizontal major axis.
\n" ); document.write( "Its standard form: $\"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\"$ , a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given ellipse:
\n" ); document.write( "center: (-6,4)
\n" ); document.write( "b^2=1
\n" ); document.write( "b=1
\n" ); document.write( "minor axis vertices: (-6,4ąb)=(-6, 4ą1)=(-6,3) and (-6,5) \n" ); document.write( "

\n" );