document.write( "Question 768150: if doubling the number of sides of a regular polygon increase the angle between adjacent sides by 10 degrees, what is the original number of sides? \n" ); document.write( "
Algebra.Com's Answer #468140 by josgarithmetic(39617)\"\" \"About 
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You could find that calculating the interior angle at each vertex, you would be using equivalent to \"180-360%2Fn\", which could also be used as \"180%281-2%2Fn%29\" for the degrees of each interior angle, at a vertex, n being the number of sides in the polygon.\r
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\n" ); document.write( "\n" ); document.write( "Now, n is an unknown variable.\r
\n" ); document.write( "\n" ); document.write( "Doubled number of sides, vertex angle 180(1-2/(2n)) degrees.
\n" ); document.write( "Original number of sides, vertex angle (180-2/n).\r
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\n" ); document.write( "\n" ); document.write( "Their difference is 10 degrees:
\n" ); document.write( "\"highlight%28180%2A%281-2%2F%282n%29%29-180%281-2%2Fn%29=10%29\"
\n" ); document.write( "\"180-180%2Fn-180%2B360%2Fn=10\"
\n" ); document.write( "\"-180%2B360=10n\"
\n" ); document.write( "\"180=10n\"
\n" ); document.write( "\"highlight%28n=18%29\" original sides, to be doubled, giving 10 degree increase at each vertex.
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