document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66084>Question 66084</A>: <I><SPAN STYLE=\"word-break: break-all;\">  2x + 3y =6 (for y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46812 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x + 3y =6 (for y)\r<BR>\n" );
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document.write( "Our approach will be to isolate y by itself on one side of the equation.  When we do that, then we will have what y equals.\r<BR>\n" );
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document.write( "First, subtract 2x from both sides:\r<BR>\n" );
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document.write( "2x-2x+3y=6-2x \r<BR>\n" );
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document.write( "(2x-2x=0 sooooo):\r<BR>\n" );
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document.write( "3y=6-2x  Now we know what three y's equal but we need to know what (1)y equals.\r<BR>\n" );
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document.write( "Next divide both sides by 3\r<BR>\n" );
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document.write( "(3y)/3=(6-2x)/3  \r<BR>\n" );
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document.write( "(3/3=1 sooooo):\r<BR>\n" );
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document.write( "y=(6-2x)/3\r<BR>\n" );
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document.write( "Hope this helps-----ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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