document.write( "Question 768013: if the width is 15 shorter than the length and the perimeter is 162 what is the dimension \n" ); document.write( "
Algebra.Com's Answer #468085 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Length = x \n" ); document.write( "Width = x - 15 \n" ); document.write( "Perimeter = 2*length + 2*width \n" ); document.write( "162 = 2(x) + 2(x - 15) \n" ); document.write( "162 = 2x + 2x - 30 \n" ); document.write( "162 + 30 = 4x \n" ); document.write( "4x = 192 \n" ); document.write( "x = 48 \n" ); document.write( "Length = 48 \n" ); document.write( "Width = 33 \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |