document.write( "Question 768013: if the width is 15 shorter than the length and the perimeter is 162 what is the dimension \n" ); document.write( "
Algebra.Com's Answer #468085 by Cromlix(4381)\"\" \"About 
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Length = x
\n" ); document.write( "Width = x - 15
\n" ); document.write( "Perimeter = 2*length + 2*width
\n" ); document.write( "162 = 2(x) + 2(x - 15)
\n" ); document.write( "162 = 2x + 2x - 30
\n" ); document.write( "162 + 30 = 4x
\n" ); document.write( "4x = 192
\n" ); document.write( "x = 48
\n" ); document.write( "Length = 48
\n" ); document.write( "Width = 33
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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