document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=768082>Question 768082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the distance between the points given.(-5/4,-7) (5/4,-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468083 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Formula is:<BR>\n" );
document.write( "Square root of(x2 - x1) ^2 + (y2 - y1)^2<BR>\n" );
document.write( "Square root of (5/4 -(-5/4)^2 + (-1 -(-7))<BR>\n" );
document.write( "Square root of (10/4)^2 +(6)^2<BR>\n" );
document.write( "Square root of (5/2)^2 + (6)^2<BR>\n" );
document.write( "Square root of 25/4 + 36<BR>\n" );
document.write( "Square root of 169/4<BR>\n" );
document.write( "= 13/2 = 6.5 units<BR>\n" );
document.write( "Hope this helps<BR>\n" );
document.write( ":-) </SPAN>\n" );
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