document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=768074>Question 768074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle if 68 feet. If the length is 8 feet more than the width, find both the length and width.  (Formula: P = 2L + 2W) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #468029 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=468029\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = width<BR>\n" );
document.write( "x + 8 = length {the length is 8 more than the width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle is 2(width) + 2(length)\r<BR>\n" );
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document.write( "2x + 2(x + 8) = 68 {substituted expressions into perimeter formula}<BR>\n" );
document.write( "2x + 2x + 16 = 68 {used distributive property}<BR>\n" );
document.write( "4x + 16 = 68 {combined like terms}<BR>\n" );
document.write( "4x = 52 {subtracted 16 from each side}<BR>\n" );
document.write( "x = 13 ft width {divided each sideb y 4}<BR>\n" );
document.write( "x + 8 = 21 ft length {substituted 13, in for x, into x + 8}\r<BR>\n" );
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document.write( "width is 13 ft <BR>\n" );
document.write( "length is 21 ft<BR>\n" );
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