document.write( "Question 7757: The perimeter of a rectangle is 260 meters. The length is 30 meters greater than its width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #4680 by bonster(299)\"\" \"About 
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P=260
\n" ); document.write( "Length=30 greater than width...so set the width as X, and set the lenth as (X+30)\r
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\n" ); document.write( "\n" ); document.write( "P=2L+2W
\n" ); document.write( "260=2(x+30)+2(X)
\n" ); document.write( "260=2x+60+2x <--subtract 60 from both sides
\n" ); document.write( "(260)-60=(2x+60+2x)-60
\n" ); document.write( "260=4x <--divide both sides by 4
\n" ); document.write( "\"260%2F4\"=\"4x%2F4\"
\n" ); document.write( "65=x\r
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\n" ); document.write( "\n" ); document.write( "since the width=x, it is 65 meters long
\n" ); document.write( "the length=x+30 or (65+30=95), it is 95 \r
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